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Uparkaam
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15 posters
+1 to the person who can . . .
bunnywink- Hollowed
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- Post n°26
Re: +1 to the person who can . . .
Wait, I thought you were gonna post another one? LOL :shock:
reim0027- Moderator
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- Post n°27
Re: +1 to the person who can . . .
I can. But, I thought it would be better if the person who guessed correctly would post a new one (and give the +1 rep to the next person). Keeps it fresh.
Uparkaam- Hollowed
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- Post n°28
Re: +1 to the person who can . . .
But wasn't Sloth the one who got the right answer first?
reim0027- Moderator
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- Post n°29
Re: +1 to the person who can . . .
Good point. Sloth - you're up.
Sloth9230- Hollowed
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- Post n°30
Re: +1 to the person who can . . .
Ughh, don't look at me... the only riddles I know can be solved through google :|
Last edited by Sloth9230 on Sun Dec 23, 2012 5:43 pm; edited 1 time in total
reim0027- Moderator
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- Post n°31
Re: +1 to the person who can . . .
Ok. I'll give a math problem. Please, don't go Google the answer. Where is the error?
Emergence- Sovereign
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- Post n°32
Re: +1 to the person who can . . .
Did I miss something?
Sloth9230- Hollowed
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- Post n°33
Re: +1 to the person who can . . .
In the picture not loading
I'm really hoping it's not my browser, then I'd feel dumb lol
I'm really hoping it's not my browser, then I'd feel dumb lol
Uparkaam- Hollowed
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- Post n°34
Re: +1 to the person who can . . .
There's an error with the picture
Sloth9230- Hollowed
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- Post n°35
Re: +1 to the person who can . . .
Uparkaam wrote:There's an error with the picture
If you open it in a new tab, you can see it.
Emergence- Sovereign
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- Post n°36
Re: +1 to the person who can . . .
In who's post?
Uparkaam- Hollowed
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- Post n°37
Re: +1 to the person who can . . .
Mozilla doesn't show anything there that could be opened in another tab. I'm gonna try Explorer.
Sloth9230- Hollowed
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- Post n°38
Re: +1 to the person who can . . .
I'm pretty sure that regardless of the numbers used, since a=b, the answer would always end up as zero. So how they got 2=1 is... confusing, or it's just wrong.
Edit: Ah I get it, it's saying that two (a - b)'s is the same as one (a-b), which technically it is. Though that's not really math.
Edit: Ah I get it, it's saying that two (a - b)'s is the same as one (a-b), which technically it is. Though that's not really math.
Last edited by Sloth9230 on Sat Dec 22, 2012 5:47 pm; edited 3 times in total
Uparkaam- Hollowed
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- Post n°39
Re: +1 to the person who can . . .
My guess:
2=1 should be 2=2
2=1 should be 2=2
reim0027- Moderator
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- Post n°40
Re: +1 to the person who can . . .
Sloth is close. But, I'm looking for the specific error (and in what step it is).
Sloth9230- Hollowed
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- Post n°41
Re: +1 to the person who can . . .
It's in the second to last step, I'm not sure what it's called though. But if they do 2(a - b) = 1(a - b) then it's (a - b)+(a - b) or (2a - 2b) = (a - b) which is (0 + 0) or (0 - 0) = 0 not 2=1
the problem is that they cancelled the (a - b) parts out and just left it as 2=1, which you can't do because the number in the parentheses is 0.
I'm only in elemntary algebra dang it, this is too hard! :evil:
the problem is that they cancelled the (a - b) parts out and just left it as 2=1, which you can't do because the number in the parentheses is 0.
I'm only in elemntary algebra dang it, this is too hard! :evil:
Last edited by Sloth9230 on Sat Dec 22, 2012 6:14 pm; edited 4 times in total
Sloth9230- Hollowed
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- Post n°42
Re: +1 to the person who can . . .
Do I have it now?
Emergence- Sovereign
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- Post n°43
Re: +1 to the person who can . . .
Where is the problem lol?
Uparkaam- Hollowed
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- Post n°44
Re: +1 to the person who can . . .
It's hidden. You have to find it
Sloth9230- Hollowed
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- Post n°45
Re: +1 to the person who can . . .
Uparkaam- Hollowed
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- Post n°46
Re: +1 to the person who can . . .
If the second last part was 2(a-b)=1(a-b) it could be solved like this (I guess):
2(a-b)=1(a-b) if I divide all of this with (a-b) it would result in this:
2=1
Which means that the last part is actually true.
The error is in the second last part. The right hand side should be 1(a-b) instead of the a-b.
2(a-b)=1(a-b) if I divide all of this with (a-b) it would result in this:
2=1
Which means that the last part is actually true.
The error is in the second last part. The right hand side should be 1(a-b) instead of the a-b.
Uparkaam- Hollowed
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- Post n°47
Re: +1 to the person who can . . .
Also, E, are you using Mozilla?
Sloth9230- Hollowed
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- Post n°48
Re: +1 to the person who can . . .
Uparkaam wrote:If the second last part was 2(a-b)=1(a-b) it could be solved like this (I guess):
2(a-b)=1(a-b) if I divide all of this with (a-b) it would result in this:
2=1
Which means that the last part is actually true.
The error is in the second last part. The right hand side should be 1(a-b) instead of the a-b.
But by divideing by (a - b) you're dividing by zero which you can't do. Booyah!
Uparkaam- Hollowed
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- Post n°49
Re: +1 to the person who can . . .
But I'm not treating (a-b) as zero at this phase. I'm treating it as (a-b).
(I don't know if that made any sense lol)
(I don't know if that made any sense lol)
Sloth9230- Hollowed
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- Post n°50
Re: +1 to the person who can . . .
I know what you mean, but the instant you start dividing by zero, the numbers themselves become meaningless since it's "undifined"
therefore you could get something like 6=1, 6=10, 100=37
or in this case 2=1
that's the mistake they made, they divided by zero
therefore you could get something like 6=1, 6=10, 100=37
or in this case 2=1
that's the mistake they made, they divided by zero
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